How Long Does it Take for a Motorcycle to Overtake a Car?

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The correct time for a motorcycle to overtake a car is 16.6 seconds, which includes the initial 7 seconds it takes for the motorcycle to reach its maximum speed. The initial calculation mistakenly covered the first 7 seconds twice, leading to an incorrect answer of 9.6 seconds. The motorcycle's position equation changes after 7 seconds, transitioning from acceleration to constant velocity. Therefore, the total time to consider is the sum of the time taken to reach maximum speed and the additional time to overtake the car. Understanding this distinction resolves the confusion in the calculations.
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Homework Statement
The motorcycle first takes the lead because its (constant) acceleration am = 8.40 m/s2 is greater than the car’s (constant) acceleration ac = 5.60 m/s2, but it soon loses to the car because it reaches its greatest speed vm = 58.8 m/s before the car reaches its greatest speed vc = 106 m/s. How long does the car take to reach the motorcycle?
Relevant Equations
ac = 5.6m/s2
am = 8.40m/s2
vcmax = 106m/s
vmmax = 58.8 m/s
2E0E3B09-8DA2-4F5E-9AF3-E51F178F3ED7.jpeg


Here is my attempt at the solution but I got the wrong answer. The right answer is t=16.6s. I know from the book (this is an example problem) that the motorcycle reaches its max speed at t=7.0s. But I don’t know where I made the mistake that is causing me to get the wrong answer afterwords.
 
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Your error lies in how you calculate the motorcycle position.
1576983971342.png

You're covering the time between 0 s and 7.0 seconds twice, since your xmo already covered that once.
 
gneill said:
Your error lies in how you calculate the motorcycle position.
View attachment 254545
You're covering the time between 0 s and 7.0 seconds twice, since your xmo already covered that once.

I don’t see why that’s a mistake. At t=7.0s the equation for the motorcycles position changes. It no longer has an acceleration, just a constant velocity. xmo is the starting point for this new position function.
 
rtareen said:
xmo is the starting point for this new position function.
The way it is written means that the ##v \times t## term assumes a starting time of ##t = 0##. That is not the case if it's contribution should only "kick in" at ##t = 7 sec##.
 
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rtareen said:
I don’t see why that’s a mistake. At t=7.0s the equation for the motorcycles position changes. It no longer has an acceleration, just a constant velocity. xmo is the starting point for this new position function.

It seems that your answer of ##9.6s## is the time starting from when the motorcycle reaches its maximum speed (after ##7s##). The answer of ##16.6s## is the time from when both vehicles start. I.e. your answer plus the ##7s##.

PS after ##9.6s## the speed of the car is ##53.76 m/s##, so it's not yet reached the speed of the motorcycle.
 
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PeroK said:
It seems that your answer of ##9.6s## is the time starting from when the motorcycle reaches its maximum speed (after ##7s##). The answer of ##16.6s## is the time from when both vehicles start. I.e. your answer plus the ##7s##.

PS after ##9.6s## the speed of the car is ##53.76 m/s##, so it's not yet reached the speed of the motorcycle.

So I just need to add 7s to the answer I got and I’ll have the correct answer. I can see why now. Thanks!
 
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