Radius of Curvature for Mirror w/ 10.0cm Candy Bar

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To determine the radius of curvature for a convex mirror when a child holds a 10.0 cm candy bar in front of it, the image size is noted to be half the object's size. The discussion emphasizes the importance of understanding the mirror formula and magnification concepts. Participants encourage the user to review class notes and apply relevant physics principles to solve the problem. The conversation highlights the need for foundational knowledge in optics to address such questions effectively. Engaging with the homework forums is suggested for further assistance.
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A child holds a candy bar 10.0cm in front of a convex mirror and notices that the image is only one-half the size of the candy bar. What is the radius of curvature of the mirror?
 
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im totally stuck sorry i didnt use the homework forums as u know I am new to the site.
 
kdl8614 said:
im totally stuck sorry i didnt use the homework forums as u know I am new to the site.
No problem, it'll get there eventually.

With respect to the question, you must have some idea. What are the concepts involved? Have you read your class notes?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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