Rate law seconds and concentration

[Mag]

could you check this?

AB(g) → A(g) + B(g)

Rate = k[AB]^2
k = 0.2L/mol∙S

How long will it take for [AB] to reach 1/3 (one third) of its initial concentration of 1.50M? What is [AB] after 10.0 seconds?

2nd order overall reaction so:
part A
1/[A] - 1/[A]o = (k)(t)
1/0.5 - 1/1.50 = (0.2)(t)
6.667 = t

part B
1/[A] - 1/1.5 = (0.2)(10 s)
[A] = 0.375

 

[Gokul43201]

Correct, and correct !

Just remember to put in the units; time in seconds and concentration in mol/L or M (molar).

 

[Mag]

okie dokie. thanks.