Ratio of RMS Speed of Oxygen to Nitrogen Molecules

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The discussion focuses on calculating the ratio of the root mean square (RMS) speed of oxygen to nitrogen molecules in a gas mixture. The molar masses provided are 32 g/mol for oxygen and 28 g/mol for nitrogen. The RMS speed can be expressed using the formula v_rms = sqrt(3RT/M), where R is the gas constant, T is the temperature, and M is the molar mass. The calculated ratio of the RMS speeds results in approximately 0.935. The confusion arises from the lack of specified quantities of each gas in the mixture, but the RMS speed equation can still be applied effectively.
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Homework Statement


A container is filled with a mixture of nitrogen and oxygen. What is the ratio of the rms speed of oxygen molecules to that of nitrogen molecules? (Molar mass of oxygen=32gmol-1; molar mass of nitrogen=28gmol-1).


Homework Equations


v2=(v12+v22+...+vN2)/N


The Attempt at a Solution


Tried using momentum mv=mv but doesn't make sense to do that (even more because the question asks for rms speed) Answer is 0.935. Can't think of sensible ways to use rms speed equation provided above. The question doesn't even specify number of molecules of each so very confused. Please help...
 
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You can express the RMS speed in terms of different quantities.

RMS speed, see the first formula.
 
Thanks
 

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