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Behold Halliday's Question and Halliday's answers:
The only force acting on a 2.0 kg body as it moves along the x axis varies as shown in Figure 741 (see attatchment). The velocity of the body at x = 0 is 4.0 m/s.
(a) What is the kinetic energy of the body at x = 3.0 m?
12 J
(b) At what value of x will the body have a kinetic energy of 8.0 J?
4.0 m
(c) What is the maximum kinetic energy attained by the body between x = 0 and x = 5.0 m?
18 J
I am stumped. I've only tried to figure out (a) and (b), but my method does not give me correct answers. My train of thought was that Delta KE=W=area under curve. So for part (a), I said that area under graph is (triangletrianglerectangle) = 4 Nm. Well, gee.
Maybe since KE is always positive, take the absolute value of various areas! I think that is very poor reasoning, because Delta KE and W can both be negative. And even when I do that, I get 8 Nm, which is still wrong.
Similar reasoning applied to (b) also gives the incorrect answer, which is comforting.
A hint from the wise gurus perhaps?
The only force acting on a 2.0 kg body as it moves along the x axis varies as shown in Figure 741 (see attatchment). The velocity of the body at x = 0 is 4.0 m/s.
(a) What is the kinetic energy of the body at x = 3.0 m?
12 J
(b) At what value of x will the body have a kinetic energy of 8.0 J?
4.0 m
(c) What is the maximum kinetic energy attained by the body between x = 0 and x = 5.0 m?
18 J
I am stumped. I've only tried to figure out (a) and (b), but my method does not give me correct answers. My train of thought was that Delta KE=W=area under curve. So for part (a), I said that area under graph is (triangletrianglerectangle) = 4 Nm. Well, gee.
Maybe since KE is always positive, take the absolute value of various areas! I think that is very poor reasoning, because Delta KE and W can both be negative. And even when I do that, I get 8 Nm, which is still wrong.
Similar reasoning applied to (b) also gives the incorrect answer, which is comforting.
A hint from the wise gurus perhaps?
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