Real Vector Spaces and the Real Spectral Theorem

jesusfreak324
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Homework Statement


Proof:Suppose that V is a real inner product space and T\in \wp(V). If (v1... vn) is a basis for V consisting of eigenvectors for T, then there exists an inner product for V such that T is self-adjoint.


Homework Equations


The Real Spectral Theorem: Suppose that V is a real-inner product space and T \in \wp(V). Then V has an orthonormal basis consisting of eigenvectors of T if.f. T is self-adjoint.

Eigenvalue / Eigenvector Problem: T(v) = \lambdav


The Attempt at a Solution


Ummm... I have spent days on trying to figure this out, and the only advice my professor gave to me was to use the real spectral theorem. But the only way to do this is by, as my professor goes on, to come up with an inner product that "turns" the basis list into an orthonormal one. But this seems like a complete contradiction... idk ~~~~
 
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I guess your n is the same as the dimension of V? Suppose it is so. Let (v,w)[/tex] be the original scalar product. Then you define new scalar product of two vectors v,w by<br /> <br /> \langle v,w\rangle=\sum_{ij}\delta_{ij} (v,v_i)(w,v_j)<br /> <br /> Your basis is now orthonormal - check it. Then play with it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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