Really Simple Magnitude Question

  • Thread starter Thread starter Heat
  • Start date Start date
  • Tags Tags
    Magnitude
AI Thread Summary
The discussion centers on whether a horizontal force applied to two crates at rest on a frictionless surface can cause them to move if the force is less than their total weight. It is clarified that the normal force cancels out the weight, allowing for movement due to an unbalanced horizontal force. The key point is that any applied force, regardless of its magnitude, will cause the crates to accelerate since there is no opposing friction. Therefore, even a small force can initiate movement. The conclusion is that the crates will indeed move due to the unbalanced horizontal forces.
Heat
Messages
272
Reaction score
0

Homework Statement


Two crates, A and B, sit at rest side by side on a frictionless horizontal surface. The crates have masses and . A horizontal force is applied to crate A and the two crates move off to the right.

If the magnitude of force is less than the total weight of the two crates, will it cause the crates to move?



The Attempt at a Solution



I already drew the force diagrams for this problem :D with no problems at all.

Now in this question, I just want to make sure that what I am thinking is correct, as I only get one try.

If the magnitude of force is less than the total weight of the two crates, then yes it would cause it too move slightly. As the normal force cancels out with the weight force, causing the "rest state".

At first I was thinking it would not, because the weight force would be bigger than the force of push, but then the force acting from box b to box a would have to be greater than the force applied for it to move.
 
Physics news on Phys.org
All you need to start the crates moving is to have an unbalanced force acting on them. The size of the net force doesn't matter. Certainly the vertical forces cancel, but what about horizontal forces?
 
so there is an unbalance of forces, since the vertical forces cancel, and there is a unbalance force in the horizontal. So it will move.
 
Heat said:
so there is an unbalance of forces, since the vertical forces cancel, and there is a unbalance force in the horizontal. So it will move.
Correct. The only horizontal force is the applied force (there's no friction to oppose it), so the crates will accelerate no matter how small that applied force is.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top