Refrigeration: The Equivalent Rate of Transport of Heat in Watts?

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Homework Help Overview

The discussion revolves around calculating the equivalent rate of heat transport in watts for a refrigeration system, specifically a 1.2 ton air conditioner that can freeze 2400 lb of ice at 0°C in a day. The original poster expresses uncertainty about how to approach the problem, particularly regarding the relationships between the quantities involved and the lack of specific heat values.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the capacity of the air conditioner to the amount of ice it can freeze but questions how this translates to heat transport in watts. They also mention a similar problem for context but seek clarification on the underlying principles.

Discussion Status

Some participants have suggested looking into the definition of "1 ton of refrigeration" to find its equivalent in kJ/s or watts, indicating a potential direction for understanding the problem. However, there is no explicit consensus on the approach to take, and the discussion remains open-ended.

Contextual Notes

The original poster notes the absence of specific heat values for heat-out or heat-in, which complicates their ability to calculate the transport of heat. This constraint is acknowledged but not resolved within the discussion.

chunkytuna21
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A 1.2 ton air conditioner has the capacity to freeze 2400 lb of ice at 0°C in a day. What is the equivalent rate of transport of heat in watts?


QH(out)= QL(in) + Wi
Coefficient of Performance= QL/ (QH-QL)
Coefficient of Performance of an Ideal System: TL/ (TH-TL)
QL/QH= TL/TH


I really don't know where to begin with this problem. I know 1.2 tons is equal to 2400lbs. So, the air conditioner and the amount of meat it freezes is a 1 to 1 ratio, but what does any of that have to do with the problem? I'm not given the heat-out or heat-in so how could I possibly calculate the transport of heat in watts? The solution to a similar problem (1 ton air conditioner and 2000lbs of meat is 3.5kW), but I need to know how to solve these type of problems.
Any help would be greatly appreciated!
 
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Take a good look at the definition of "1 ton of Refrigeration". Find out how many kJ/s or (Watts) that one ton of refrigeration is equivalent to.

Thanks
Matt
 
Last edited:
Thanks! That was a lot simpler than I expected it to be.
 
Glad that I could help.

Thanks
Matt
 

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