Regarding ' The Electric field inside a non conducting shell '

AI Thread Summary
The discussion centers on calculating the electric field inside a uniformly charged non-conducting spherical shell with an external point charge. The initial approach using Gauss's law suggests that the electric field inside the shell is zero due to no enclosed charge, but this conclusion is questioned. Participants highlight that the assumption of the electric field being constant within the Gaussian surface is incorrect. The symmetry of the spherical shell indicates that it generates no electric field inside itself regardless of external charges. Therefore, the correct interpretation is that the electric field inside the shell remains zero.
Uday
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Homework Statement


There is a Uniformly charged Non conducting Spherical shell along with a point charge external to the shell . they make up an isolated system . Find the electric field inside the shell .


Homework Equations





The Attempt at a Solution

Actually using superposition principle we obtain that the field is actually non zero . But in order to calculate the electric field inside the shell if i use gauss law by considering a gaussian surface inside the shell ... there will be no charge enclosed in it so by gauss law the flux is zero . since in that case ∫E.da = E∫da which is equal to zero . Since ∫da is non zero E must be zero ...
I guess there is some fault with this but I am unable to find it out . So please can u help me .
And thanks for sparing ur valuable time to read this .
 
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Uday said:
∫E.da = E∫da
That will not be true in general. Is anything known about the shape of the shell?
 
haruspex said:
That will not be true in general. Is anything known about the shape of the shell?

Im sorry that's a spherical shell
and i have edited my question .
 
Last edited:
Hello Uday

Uday said:
Actually using superposition principle we obtain that the field is actually non zero . But in order to calculate the electric field inside the shell if i use gauss law by considering a gaussian surface inside the shell ... there will be no charge enclosed in it so by gauss law the flux is zero . since in that case ∫E.da = E∫da which is equal to zero . Since ∫da is non zero E must be zero ...
I guess there is some fault with this but I am unable to find it out . So please can u help me .
And thanks for sparing ur valuable time to read this .

I think the problem lies in concluding that if the flux across the gaussian spherical surface is zero ,then the electric field is zero .

What is your reasoning behind moving E out of the integral ∫E.ds ?
 
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Ya ... that's ryt E isn't constant ...
 
Uday said:
Im sorry that's a spherical shell
and i have edited my question .
OK, so forget the point charge for the moment. What field does a uniformly charged spherical shell generate inside itself?
Hint: when considering a Gaussian shell placed concentrically inside it, think about the symmetry.
 
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