As I understand it, temperature is really a measure of the average motion of particles. In SR when an object is going at a speed appreciable to the speed of light it will be time dilated, length contracted etc.(adsbygoogle = window.adsbygoogle || []).push({});

But what if we were to measure its temperature; since it is going a lot faster won't its temperature be much larger (hotter) compared to its rest temperature?

Is there a formula for this?

is it just that T'= Trest*gamma where gamma is just (1-v^2/c^2)^(-1/2)?

thank you

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# Relativity and Temperature

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