Relativity of Simultaneity Question

jowens1988
Messages
15
Reaction score
0

Homework Statement


The space and time coordinates for pairs of events are (ct,x,y)1 = (0.3,0.5,0.6) meters and (ct,x,y)2 = (0.4,0.7,0.9) meters. Could there be a causal connection between these two events? Is there a frame in which the two events would be recorded as simultaneous? If so, what is this frame?

Homework Equations


s2 = (ct)2 - (x)2 - (y)2

The Attempt at a Solution


I understand that if s2 is negative, which in this case I get that it is, then the events cannot be causally related. But I tried to use a different method of solution, and I was just curious if it is correct:

I plot the x and y coordinates given in the problem statement in the x-y plane, and take the ct coordinates to be a third dimension, the height above the x-y plane. I find the distance between the points given in the x-y plane, which I get in this case to be:

d = ((0.7-0.5)2 - (0.9-0.6)2)1/2 = 0.360555m

Then, I want to find the slope of the line connecting these points (including the ct coordinate, so it is a line in a plane that contains the line that connects the points in the x-y plane, with height value ct), which I get to be

slope = (ct2 - ct1)/(0.360555) = 0.27735 < 1 => you would have to travel faster than the speed of light for these two events to be causally related.

Now, I want to see if there exists a frame S' with some velocity v in which these two events can be considered simultaneous:

Or, mathematically: delta t' = 0

I make a new coordinate system, in which I keep the ct coordinate, but I combine the x and y coordinates, where (x,y)1 = z1 = 0 and (x,y)2 = z1 = 0.360555m (the distance between the two x-y coordinates.)

Given that t' = gamma/c(ct-beta*z1) from the Lorentz transformation, i can derive that the necessary v =

-c2(t2 - t1)/(z1-z1)

Which I get to be greater than the speed of light, so they cannot be simultaneous.

Is this thinking correct? Is there an easier way to do this?

If two events aren't causally connected, can they ever be simultaneous?

Thank you!
 
Last edited:
Physics news on Phys.org
cΔt=c(t2-t1) is less than z2, right? So you can find a β<1 such that cΔt = β z2. I think you just made an algebra error solving for the speed.
 
vela said:
cΔt=c(t2-t1) is less than z2, right? So you can find a β<1 such that cΔt = β z2. I think you just made an algebra error solving for the speed.

Okay, that's right. I re-worked the algebra, and I can find such a β.

So, the moral of the story is that even if two events aren't causally related, they CAN still be simultaneous?
 
Right. They're mutually exclusive, actually. If two events are causally related, they're timelike or lightlike separated, so they can't be simultaneous. Similarly, if two events are simultaneous, they are spacelike separated, so they can't be causally related.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top