Replacing a hollow shaft with a solid shaft

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To determine the diameter of a solid shaft replacing a hollow shaft, one must consider the maximum shear stress and torque applied to both. The maximum shear stress is given as 35.8 x 10^6 and the torque as 450.117 x 10^3. The polar moment of inertia (J) for the hollow shaft needs to be calculated using its external and internal diameters, which are 400mm and 200mm, respectively. It's important to apply the correct formulas for shear stress and polar moment of inertia, as the approach differs from replacing a solid shaft with a hollow one. Seeking clarification on these calculations can help ensure accurate results.
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Homework Statement



" determine the diameter of a replacement solid shaft manufactured from the same material and subjected to the same maximum shear stress and torque"

Ok so I previously calculated the following:

Maximum shear stress= 35.8 x 106
Torque= 450.117 x 103
Hollow shaft external and internal diameters= 400mm and 200mm

Homework Equations



T/J = shear stress/r

J= Pi x d4/32

r= D/2

The Attempt at a Solution



Basically I attemted it in a very long winded way which was found to be wrong when I went through it with my tutor. What happened was I went off an example we done in class which was similar but for replacing a solid shaft with a hollow one whereas I am wanting to replace a hollow shaft with a solid one. I've read the rules on here and I know its not a place to get your assignments done for you but I was hoping someone would be able to give me an explanation and point me in the right direction as my tutor isn't being to helpful. Cheers.
 
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stainton1: Hint: Look up or write the formula for polar moment of inertia, J1, of a round tube. Set shear stress tau1 = tau2. Substitute.
 
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Isn't there a difference in the equations for a thin versus thick-walled hollow shaft?
 
DannoXYZ: In the limit, yes, you can obtain a different, approximate formula for a thin tube. But why bother with an approximate formula, when you can instead use the exact formula. Besides, stainton1 does not have a thin tube.
 
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