Requirements for a Tangent at the Origin: Function Analysis

  • Thread starter Thread starter Jan Hill
  • Start date Start date
  • Tags Tags
    Origin Tangent
Jan Hill
Messages
63
Reaction score
0

Homework Statement



What must hold true for a function to have a tangent at the origin.

Eg. Given f(x) = 0, x = 0

and f(x0 = xsin (1/x) x does not equal 0

will the graph have a tangent at the origin?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Jan Hill said:

Homework Statement



What must hold true for a function to have a tangent at the origin.

Eg. Given f(x) = 0, x = 0

and f(x0 = xsin (1/x) x does not equal 0

will the graph have a tangent at the origin?

Homework Equations


It must have a finite derivative when x = 0. Check its difference quotient.
 
What is a finite derivative?
 
Jan Hill said:
What is a finite derivative?

Have you had or are you taking calculus? If so then you should know what a derivative is. A function has a finite derivative at a point if its derivative at that point exists and is finite.

Geometrically this means that the graph of the function is smooth enough at the given point that it has a tangent line that is not vertical.

To work this problem you need to analyze

\lim_{h\rightarrow 0}\frac{f(0+h)-f(0)} h

for your function

f(x) = x\sin\frac 1 x,\ f(0)=0
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top