Resistance grows with temperature

AI Thread Summary
The resistance of copper windings in an electric motor increases from 54Ω at 20°C to 60Ω at an unknown temperature. Using the formula R1=R0(1+αt1) with α=0.00393, the initial resistance R0 is calculated to be approximately 50.06Ω. The subsequent calculation yields a temperature of about 50.5°C for the resistance of 60Ω. There was confusion regarding the book's answer, which was found to be incorrect. The calculations presented are validated, indicating the potential for errors in reference materials.
Karol
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Homework Statement


The copper windings in an electric motor have a resistance of 54[Ω] at 200.
Later the resistance was 60[Ω], what is the temperature

Homework Equations


$$R_1=R_0(1+\alpha t_1)$$
α=0.00393[1/0]

The Attempt at a Solution


At 00C R0 is: ##54=R_0(1+0.00393\cdot 20)\rightarrow R_0=50.06##
##60=50.06(1+0.00393\cdot t_2)\rightarrow t_2=50.5^0##
It should be t2=2860C
 
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And your question is what?
 
If i am right and the book is wrong.
 
Your math looks good. Books have been known to be in error.
 
Thanks and now i saw i read the wrong answer in the book, but thanks anyway for the effort
 
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