A hollow cylinder is .012 m long and has an inner radius of 0.005 m and an outer radius of .0175 m. Treat each surface (inner, outer, and the two end faces) as an equipotential surface. Resistivity of material making the cylinder = 9.68 x 10^-8 Ohm*m 1. At room temperature, what will an ohmmeter read if it is connected between the inner and outer surfaces? 2. Relevant equations R=rho/(2pi*L) (ln (b/a)) 3. The attempt at a solution My professor worked this problem out and got 851 Ohms but I cannot figure out how. Any help is greatly appreciated.