Resistor and power output varying with a distance x

Click For Summary

Homework Help Overview

The problem involves a circuit with a battery connected to a uniform resistor, where a sliding contact can vary the resistance based on its position. The goal is to find an expression for the power dissipated in the resistor as a function of the sliding contact's position.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the configuration of resistors and the relationship between the sliding contact position and the resistance. There is uncertainty about how to approach the problem, particularly regarding the parallel and series arrangements of resistors.

Discussion Status

Some participants have suggested breaking down the circuit into parts and calculating the voltage and current through the resistor. Others are seeking clarification on the problem and expressing confusion about the setup and calculations involved.

Contextual Notes

There is mention of needing to plot the function for specific values, indicating that numerical analysis may be part of the problem. Participants are also encouraged to share images for better understanding.

Jonnyto
Messages
12
Reaction score
0

Homework Statement


Figure 29 shows a battery connected across a uniform resistor R0. A sliding contact can move across the resistor from x=0 at the left to x=10 cm at the right. Find an expression for the power dissipated in the resistor R as a function of x. Plot the function for ℰ=50 V, R=2000Ω , and R0=100Ω


Homework Equations


P=[itex]\frac{V<sup>2</sup>}{R}[/itex]



The Attempt at a Solution


I have no clue at all on how to solve this problem. I think that it might have to do with how resistors are adding up in parallel. I really can't see which one is in parallel. I don't see how to determine the resistance with the varying x.

fig29.JPG
 
Physics news on Phys.org
This circuit is equivalent to three resistors: Rl, Rr, and R. Rl and Rr are the left and right, correspondingly, parts of Ro; their values depend on x. Solve for voltage at R and current through it.
 
It's helpful to post a full size image if it's not too large.

attachment.php?attachmentid=58418&d=1367488623.jpg
 
may be this be help..
[itex]R_{total}=(R // R_{p}) + R_{s})[/itex]
upload1.JPG


just as Voko said #2
 
Complex

arifz2303 said:
may be this be help..
[itex]r_{total}=(r // r_{p}) + r_{s})[/itex]




just as voko said #2

please explain more about the problem
 
Last edited by a moderator:

Similar threads

  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 60 ·
3
Replies
60
Views
11K
Replies
9
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
4K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
Replies
25
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 24 ·
Replies
24
Views
6K