Calculating Equivalent Resistance of Resistor Network

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The discussion focuses on calculating the equivalent resistance of an infinite resistor network. The proposed formula for equivalent resistance is Req = 1/2 [(4RtRl + Rt^2)^(0.5) + Rt]. Participants suggest starting with the first three resistors to derive an expression, leading to the conclusion that the circuit can be simplified by treating the remaining resistors as a single equivalent resistance R. By setting up the equation R*Rl/(R+Rl) + Rt = R, the solution can be derived. The conversation emphasizes the recursive nature of the problem in infinite circuits.
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Homework Statement



Show that the equivalent resistance is Req = 1/2 [(4RtRl + Rt^2)^(.5) + Rt]
http://img74.imageshack.us/img74/5905/pingib2.png

Homework Equations


The Attempt at a Solution



So far all I can get is Req = Rt + Rl Rt/(Rt+Rl) from the first three resistors starting from the left. I suppose I could take that and add it to the next branch Rl Rt/(Rt+Rl), but that would appear to go on to infinity as opposed to stopping at a nice number.

Does anyone have any hints on finding the eq. resistance?
 
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I believe by recursion.

Everything to the right of RL is parallel with RL, and in series with RT.
 
Since this is an infinite circuit, ignore the first rt and rl, and assume the resistance of the rest to be R. This give you:

R*rl/(R+rl) +rt=R. As the resistance of the total circuit is also R. Solve for R to get your answer.
 
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