- Homework Statement
- Two resistors, R1 and R2, are connected in parallel to a power supply that has voltage V and negligible internal resistance. R2 = 9.00 Ω and the resistance of R1 is not known. For several values of V, you measure the current I flowing through the voltage source. You plot the data as I versus V and find that they lie close to a straight line that has slope 0.168 Ω^−1.
- Relevant Equations
- V = IR
1/Rtot = 1/R1 +1/R2
Since the slope of the I versus V graph is equal to 1/R, I set Rtot equal to 0.168. So then I subtracted 1/0.168 by 1/9 and got 1/R1 =5.841. I then found R1 equal to 1/5.841 or 0.171 but it said I was wrong. Can someone tell me what I did wrong?