Resonace frecuency and peak current

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The discussion centers on calculating the resonance frequency of a circuit where the reactance of the capacitor equals the reactance of the inductor (Xc = XL). The user initially calculated the resonance frequency using the formula 2πfL = 1/(2πfC) and arrived at a value of 5032.92 Hz, which they believe is too high. Another participant confirms that the calculation appears correct, suggesting the user may need to double-check their circuit parameters or assumptions. The conversation emphasizes the importance of accurate component values in resonance frequency calculations. Ultimately, verifying the circuit setup and component specifications is crucial for accurate results.
Xaspire88
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For the circuit shown
a. What is the resonance frequency?
b. At resonance, what is the peak current through the circuit?

http://img218.imageshack.us/img218/2971/p56dr3.png

I solved for resonance frequency knowing that when Xc=XL you get a resonance frequency.
my set up was

2pifL=1/(2pifC)

and then i solved for f... but the number i got was 5032.92 and this seems way too big.
 
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Please help me out. Thank you.:cry:
 
I think your calculation of the frequency is correct.
 

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