Resultant velocities from 2D collision

AI Thread Summary
To calculate the resultant velocities from a 2D collision of two circles with known velocities, one must consider the angles of impact and the conservation of momentum. If the angle difference between the two circles is zero, momentum transfers completely; as the angle approaches 90 degrees, momentum transfer diminishes. The discussion highlights the importance of resolving velocities along the center-to-center line of the circles during impact. The concept of elasticity is clarified, indicating that the circles are treated as having no non-conservative forces affecting the collision. This approach allows for accurate calculations in programming simulations of circle collisions.
Hurpadurp
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Homework Statement


Suppose you have two 2D circles, where size ≈ mass, each of which is moving with known x- and y-velocities. The two collide, not necessarily head-on (one could broadside the other, etc). How do I calculate the resultant velocities, assuming no elasticity or friction?

Homework Equations


ρ = mv
m1v1 + m2v2 = m1v1` + m2v2`
Speed = Square root of (X-velocity^2 + Y-velocity^2)

The Attempt at a Solution


Each circle is moving in a particular angle (direction), and hits the other at a particular angle. If the difference between angles is 0, then the mower transfers all of its momentum to the other. If the difference is approaching 90 degrees, then the amount transferred is approaching 0.I apologize if this has already been answered; I couldn't find it.
Thanks!
 
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Hurpadurp said:

Homework Statement


Suppose you have two 2D circles, where size ≈ mass, each of which is moving with known x- and y-velocities. The two collide, not necessarily head-on (one could broadside the other, etc). How do I calculate the resultant velocities, assuming no elasticity or friction?

Homework Equations


ρ = mv
m1v1 + m2v2 = m1v1` + m2v2`
Speed = Square root of (X-velocity^2 + Y-velocity^2)

The Attempt at a Solution


Each circle is moving in a particular angle (direction), and hits the other at a particular angle. If the difference between angles is 0, then the mower transfers all of its momentum to the other. If the difference is approaching 90 degrees, then the amount transferred is approaching 0.


I apologize if this has already been answered; I couldn't find it.
Thanks!

Hello Hurpadurp,
What do you mean by size ≈ mass?And what is the constraint "no elasticity"?Do you mean that the balls are identical and the collision is assumed to be elastic without any non conservative forces? If yes try to resolve the velocities along the center to center line of spheres at the time of impact.You will be done.
regards
Yukoel
 
Yukoel,

Here's a little more information on why I'm asking this:
I'm making a program in which objects, represented by circles, are moving around on the screen. When they hit each other, a collision function is called - the size of the circle is the same as its mass; e.g. circles of radius 70 units have half the mass of circles of radius 140 units. For ease of use, let's say the units are meters, and convert nicely to kilograms; the speeds are in m/s.
I'm unfamiliar with the concept of elasticity (my recent college courses just dealt with head-on collisions with either negligible or a specific amount of friction). In here, there are no non-conservative forces.

I'm sorry, but what do you mean by resolving "the velocities along the center to center line of spheres at the time of impact?"

Thanks,
Hurpadurp

Edit: A little more information: I checked http://en.wikipedia.org/wiki/Elastic_collision#Two-_and_three-dimensional but I don't quite understand if it's explaining the situation for the second particle being at rest, or more generally.
 
Last edited:
Hurpadurp said:
Yukoel,

Here's a little more information on why I'm asking this:
I'm making a program in which objects, represented by circles, are moving around on the screen. When they hit each other, a collision function is called - the size of the circle is the same as its mass; e.g. circles of radius 70 units have half the mass of circles of radius 140 units. For ease of use, let's say the units are meters, and convert nicely to kilograms; the speeds are in m/s.
I'm unfamiliar with the concept of elasticity (my recent college courses just dealt with head-on collisions with either negligible or a specific amount of friction). In here, there are no non-conservative forces.

I'm sorry, but what do you mean by resolving "the velocities along the center to center line of spheres at the time of impact?"

Thanks,
Hurpadurp

Edit: A little more information: I checked http://en.wikipedia.org/wiki/Elastic_collision#Two-_and_three-dimensional but I don't quite understand if it's explaining the situation for the second particle being at rest, or more generally.
Hello Hurpaderp,
Um I made this image here at http://img823.imageshack.us/img823/4985/f5461f6608dd48fdb74f6a2.png (I am bad at paint and photoshop so sorry :( )
I think it is kinda what your situation demands.The center to center line is the red line(in the picture).Resolve velocities along this line and apply expressions for final velocities on them like two masses colliding with given initial velocities.The tangential component(the component perpendicular to the red line) remains untouched.The wiki link shows a stationary equal mass being acted upon by the collision.This is why the final trajectories of both are perpendicular.
Hoping this helps.
regards
Yukoel
 
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