Resulting force after two objects collide

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In a head-on collision between two cars, Car A (4000 lb, 3 ft/s) exerts an impact force of 900 lb to the left on Car B (2000 lb, 6 ft/s). According to Newton's third law, Car B experiences an equal and opposite force, suggesting it should feel a force of 900 lb to the right. However, the discussion raises the question of whether Car B's higher velocity affects the impact force experienced. Ultimately, the consensus is that despite the differing velocities, the force on Car B remains 900 lb to the right, aligning with Newton's third law. Understanding the relationship between force and velocity in collisions is crucial for solving such problems.
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Homework Statement


The car A has a weight of 4000 lb and is traveling to the right at 3 ft/s. Meanwhile a 2000 lb car B is traveling at 6 ft/s to the left. If the cars crash head-on, and at a time instant during the crash the impact force on A is 900 lb to the left, what is the magnitude and direction of the impact force exerted on B at the instant?

So essentially,

Car A (4000 lb; v= 3 ft/s) → ← Car B (2000 lb; v = 6 ft/s)

A) 900 lb to the left
B) 450 lb to the left
C) 450 lb to the right
D) 1800 lb to the left
E) 900 lb to the right

Homework Equations


F1=F2 ?

The Attempt at a Solution


This is a question in my Statics homework and we have only been learning about forces and haven't concerned ourselves with the role that v has to play. This seems like something I learned in my first class of Newtonian physics a long time ago that I can't recall.

From a theoretical standpoint, I might assume that due to Newton's third law, everything has an equal and opposite reaction, that Car A would exert the same amount of force on B: the force on car B would be 900 lb to the right.

But then, I imagine that because Car B has a greater velocity, A would have less of an impact on it.

So I assume the answer is either C or E.
Is there an equation I can use to account for velocity and Force? I tried googling it and couldn't find anything.
Thanks!
 
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Newton's third law.
 
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I feel you should go by Newtons 3rd law itself.
 
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I went with Newton's third law and got it right! Thanks!
 
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