Reversible Heating and Cooling

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Discussion Overview

The discussion revolves around the thermodynamic properties of an ideal gas during reversible heating and cooling processes, specifically focusing on changes in internal energy (ΔU), enthalpy (ΔH), heat (q), and work (w) under constant pressure and constant volume conditions. The context includes homework-related questions and attempts at solutions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that for reversible heating at constant pressure, all values except heat (q) are negative, with q being positive due to heat being added.
  • Another participant questions how the first contributor determined that ΔU and ΔH are negative, seeking clarification on their reasoning.
  • For reversible cooling at constant volume, one participant notes that work (w) is zero and that q equals ΔU, with q being negative as heat is removed.
  • There is a mention that the definition of enthalpy (H) may help in determining whether ΔH is positive, negative, or zero.
  • One participant expresses uncertainty about calculating ΔH and seeks guidance on its definition in terms of U, P, and V.

Areas of Agreement / Disagreement

Participants are engaged in clarifying concepts and reasoning, but there is no consensus on the values of ΔU, ΔH, q, and w for the scenarios presented. Multiple viewpoints and uncertainties remain regarding the signs and calculations of these thermodynamic properties.

Contextual Notes

Participants have not fully resolved the definitions and relationships between the thermodynamic properties, particularly regarding ΔH, and there are assumptions about the behavior of ideal gases that may affect the discussion.

Who May Find This Useful

Students studying thermodynamics, particularly those interested in the properties of ideal gases and reversible processes, may find this discussion relevant.

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Homework Statement



I have two problems.

What is Delta U, Delta H, q, and w for the Reversible heating of an ideal gas at constant P.

Also, what are these values for the Reversible cooling of an ideal gas at constant V.

Homework Equations





The Attempt at a Solution



For the first equation I decided that all values would be negative except for heat which is positive. I consider this because w=-pex(deltaV) and I decided q= positive because when u are heating somethign you add heat.

for the second problem I know work=0 because the system is at constant volume. Also, q=Delta U because Delta U=q+w. q is negative because soemthing that is cooling is removing heat. I can not figure out delta H.
 
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Are you being asked to provide the expressions for ΔU, etc., in terms of P and V? Or just to state whether they are positive, negative, or zero?

For the first equation I decided that all values would be negative except for heat which is positive. I consider this because w=-pex(deltaV) and I decided q= positive because when u are heating somethign you add heat.
That's good reasoning on w and q. How did you figure out that U and H are negative?

for the second problem I know work=0 because the system is at constant volume. Also, q=Delta U because Delta U=q+w. q is negative because soemthing that is cooling is removing heat.
Looks good so far.
I can not figure out delta H.
What is the definition of H?

Also, the fact that it is an ideal gas might or might not come into play.
 
H is enthalpy. I just have to say whether or not the values of these will increase decrease or if they are zero in each case. I am really only concerned about the last two.
 
How is enthalpy H defined in terms of U, P, and V? You can use this defining equation to work out whether ΔH is +, -, or 0.
 

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