Revolutions of and Electric Drill

AI Thread Summary
A variable speed electric drill motor accelerates from 100 rev/s to 210 rev/s at a rate of 53.0 rev/s². The initial calculation of 15,700 revolutions was incorrect. To find the correct angular displacement, the formula Vf² = Vi² + 2ax is adapted for angular motion. By substituting angular velocity and acceleration into the equation, the correct displacement can be determined without converting to radians. The user successfully resolved the problem with this approach.
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1. A variable speed electric drill motor turning at 100 rev/s is uniformly accelerated at 53.0 rev/s2 up to 210 rev/s. How many turns does it make in the process?



2. (Accel f - Accel) i x speed



3. I took 210 - 53 = 157 and multiplied that by 100 and that gave me 15,700 rev. This anser is incorrect. Please advise.
 
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Data we have: Initial angular velocity, acceleration, final angular velocity. We want angular displacement.

This problem is the rotational analogue of one we would use the for the equation Vf^2 = Vi^2 + 2ax.

Replace V with angular velocity, a with acceleration and solve for x. Since we are working in units of rev, no division by 2*pi will be necessary - the answer your calculator gives you will be the answer you want.
 
I got it! Thanks so much for your help.
 
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