Rieman Integral: The Fundamental Theorem of Calculus

kingstrick
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Homework Statement



Let I := [a,b] and let f: I→ℝ be continuous on I. Also let J := [c,d] and let u: J→ℝ be differentiable on J and satisfy u(J) contained in I. Show that if G: J→ℝ is defined by

G(x) :=∫u(x)af for x in J, then G'(x) = (f o u)(x)u'(x) for all x in J.


2. The attempt at a solution

I am not sure what theorem to use in this situation. I am thinking that the product and composition of differentiable functions means that G'(x) exists...but I don't believe that will help me in this situation. Any ideas as to how i should start this one?
 
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The Leibniz formula that Dick links to is basically using the chain rule.

If F(x)=\int_a^{g(x)} f(t)dt let u= g(x) so that the integral is
\int_a^u f(t)dt and, by the Fundamental theorem of Calculus,
\frac{d}{du}\int_a^u f(t)dt= f(u)

Now, use the chain rule to find the derivative with respect to x.
 
I don't understand. Isn't the derivative of G(x) the f in the integral. Or am i supposed to find the derivative of F(X)?
 
No, the derivative of G(x) is NOT "the f in the integral". If the upper limit were just "x" it would be.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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