Rocket Engine Failure: Calculating Velocity at 1055m/s | 21.1*50 = 1055

Thread starter Jregan
Start date Sep 1, 2019
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Algebra based physics Engine Max height Physics Rocket Rocket engine

In summary, rocket engine failure refers to the malfunction or breakdown of a rocket's propulsion system, potentially preventing the rocket from reaching its intended destination. Velocity can be calculated by dividing the distance traveled by the time it took to travel that distance. This information is significant in analyzing the cause of failure and preventing similar incidents in the future. Factors such as mechanical malfunctions, technical errors, and external forces can contribute to rocket engine failure, highlighting the importance of careful monitoring and testing. To prevent failure, rigorous testing, quality control measures, and improvements in rocket design are necessary.

Sep 1, 2019

Jregan

Homework Statement: A rocket accelerates vertically with a constant acceleration of 21.1m/s/s until it’s engine fails after 50 seconds. The rocket reaches an altitude of 26375m when the engine fails. When does the rocket reach its max height? (Ignoring air resistance)
I don’t understand how the equations given in the hint work with this question.

Relevant Equations: The hint says vi=a*delta t and vf=vi-g*delta t

21.1*50=1055
1055m/s is the velocity when the engine fails.
I don’t know what the time should be in the second equation.

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Sep 1, 2019

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Jregan said:

21.1*50=1055
1055m/s is the velocity when the engine fails.

Good. Take the instant that the engine fails to be the beginning of the second phase of the motion.

1. What is the significance of calculating velocity at 1055m/s in rocket engine failure?

The velocity at which a rocket engine fails is important because it can help us understand the cause of the failure and make improvements for future designs. Additionally, knowing the velocity at failure can help engineers make decisions about the safety of the rocket and its payload.

2. How is the velocity at 1055m/s calculated in rocket engine failure?

The velocity at 1055m/s is calculated by multiplying the speed of the rocket, which is 21.1 meters per second, by the time of 50 seconds. This calculation assumes that the rocket is moving at a constant speed and does not take into account any external factors that may affect the velocity.

3. What factors can contribute to a rocket engine failure at 1055m/s?

There are several factors that can contribute to a rocket engine failure at 1055m/s, including mechanical malfunctions, fuel or oxidizer depletion, and external disturbances such as wind or turbulence. It is important for engineers to thoroughly test and monitor all components of the rocket to minimize the risk of failure.

4. How does the velocity at 1055m/s compare to the average speed of a rocket engine?

The velocity at 1055m/s may be considered relatively fast compared to the average speed of a rocket engine, which is typically around 5000m/s. However, the specific velocity at which a rocket engine fails can vary greatly depending on the design and conditions of the rocket launch.

5. Can the velocity at 1055m/s be used to predict future rocket engine failures?

While knowing the velocity at which a rocket engine failed can provide valuable information, it is not a reliable predictor of future failures. Each rocket launch is unique and can be affected by a multitude of factors, making it difficult to accurately predict future failures based on past velocities.