(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A metal alloy rod is submerged 15 cm below the surface of a fresh water pool by steel cables tied 10cm from each end. It has a length of 110 cm, a mass of 1.5 kg and a uniform square cross sectional area of 5 cm2. Because its density is not uniform, its center of mass is located 30 from the left end. The total depth of the water is 45 cm.

a) What is the force of tension on the left cable?

b) What is the force of tension on the right cable?

2. Relevant equations

T = F*d

Fb = ρgV

F = ma

F_{tension}= -F_{buoy}+ F_{grav}+ F_{waterpress}

3. The attempt at a solution

I have three 5 forces acting on the rod.

- The pressure of the water pressing down on the rod

- The force of gravity acting down on the rod (@ center of gravity 30cm from the left end)

- The buoyant force acting up on the rod (@ the same point as the gravitational force)

- Tension from the wire on the left end

- Tension from the wire on the right end

Since there is no rotation on the rod the sum of the torques must be zero. Since there is no motion on the rod, the sum of the forces must also be zero.

I believe I need to include the torques in the solution someplace but I'm just not seeing it.

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# Homework Help: Rod Suspended in Fluid

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