Rolling motion linear and translation equation

AI Thread Summary
In rolling motion on a rough surface, the frictional force can be considered static friction since the point of contact is at rest. This static friction can be represented as kmg, where k is the coefficient of static friction. During rolling without slipping, the friction does not perform work because it acts over no distance, allowing energy conservation without dissipation. However, the maximum static friction force is limited to kN, and it is important to note that simply stating "sufficient friction exists" does not imply that static friction equals kN in all cases. Understanding these nuances is crucial for accurately analyzing rolling motion dynamics.
ambuj123
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Hello
well i have a very basic doubt
well when we have a rolling motion
and surface is rough
then what i used to do was write linear and translation equation and find f (Frictional force)
Now is this frictional force same as static friction and can we write is as kmg where k is coeffecient of static friction assuming since point of contact is at rest so static friction acts.
Please help
further if friction acts during rolling motion we know energy remains conserved and no dissipation takes place but does that mean frictional force does no work
thanx
 
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There's a different constant known as the coefficient of rolling friction, which is what you must apply.

http://webphysics.davidson.edu/faculty/dmb/PY430/Friction/rolling.html
 
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During rolling without slipping, the point of contact is instantaneously at rest. So when an object rolls without slipping on a surface, the friction acting corresponds to static fricton.
Since the point of contact is instantaneously at rest, the friction force does not act over any distance and therefore does not change the total energy.
Also, the maximum possible force by static friction is given by kN. So, in most questions, where it is only mentioned that sufficient friction to prevent slipping exists, you can't use the static friction as kN.
 
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