Rolling Objects, Friction, and Newton's Second Law

AI Thread Summary
In the discussion on rolling objects and friction, participants explore the dynamics of a ring rolling down an incline and the implications of Newton's laws. The equations for torque and force are questioned, particularly when the incline angle θ equals zero, leading to confusion about the role of static friction. It is clarified that static friction is not a defined force but rather has a maximum value, allowing the ring to maintain uniform velocity without rolling friction. Additionally, the behavior of a yoyo when pulled vertically is examined, concluding that while it may rise and rotate, it does not move horizontally without a net force. The conversation emphasizes the importance of understanding torque and friction in rotational dynamics.
Starwing123
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Homework Statement


In rotational dynamics, a typical problem would be along the lines of a ring with mass m and radius r rolling down a hill with angle θ to the horizontal. Find the acceleration of the ring.



Homework Equations


Ʃτ=I\alpha = r x (friction)
ƩF = ma = mgsinθ - (friction)

The Attempt at a Solution


These equations usually give the correct answer for the problem (plug in the numbers, isolate, solve for whatever the question asks). My question is that these equations don't seem to make sense if θ=0. That would imply that F = -(friction) and the ring is slowing down (if it was moving originally). However, that is not the case if there is no rolling friction. Why does this equation break down?

A similar dilemma I have is given a yoyo on the floor, if you pull vertically up on the string, the yoyo rolls in a certain direction. However, there is no net force horizontally, so how does it roll? If the answer is that the torque causes it, when why would Newton's second law even apply in the case of yoyos rolling down a string in midair?
 
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Starwing123 said:

Homework Statement


In rotational dynamics, a typical problem would be along the lines of a ring with mass m and radius r rolling down a hill with angle θ to the horizontal. Find the acceleration of the ring.



Homework Equations


Ʃτ=I\alpha = r x (friction)
ƩF = ma = mgsinθ - (friction)

The Attempt at a Solution


These equations usually give the correct answer for the problem (plug in the numbers, isolate, solve for whatever the question asks). My question is that these equations don't seem to make sense if θ=0. That would imply that F = -(friction) and the ring is slowing down (if it was moving originally). However, that is not the case if there is no rolling friction. Why does this equation break down?

It does not break down. It simply means that the static friction is zero and the ring rolls with uniform velocity. You know that static friction is not a defined force, you only know its maximum possible value.

Starwing123 said:
A similar dilemma I have is given a yoyo on the floor, if you pull vertically up on the string, the yoyo rolls in a certain direction. However, there is no net force horizontally, so how does it roll? If the answer is that the torque causes it, when why would Newton's second law even apply in the case of yoyos rolling down a string in midair?

The yoyo will not start to move horizontally if you pull the string exactly vertical. But it will rise a bit, detached from ground and starting to rotate...


ehild
 
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