Rolling Steel Ball Acceleration Questions

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SUMMARY

The discussion centers on the motion of a steel ball rolling down one slope and up another, with specific focus on calculating acceleration and time. The ball takes 2.5 seconds to reach a speed of 5.0 m/s at the bottom of the first slope, allowing for the calculation of acceleration using the formula v = at, resulting in an acceleration of 2.0 m/s². Given that the acceleration on the second slope is half that of the first, the ball's deceleration on the second slope is 1.0 m/s². Consequently, it will take 5.0 seconds for the ball to come to a complete stop on the second slope.

PREREQUISITES
  • Understanding of basic kinematics, specifically the equations of motion.
  • Familiarity with the formula v = at for calculating acceleration.
  • Knowledge of the concept of acceleration and deceleration.
  • Ability to perform basic algebraic calculations.
NEXT STEPS
  • Study the equations of motion in detail, focusing on their applications in real-world scenarios.
  • Learn about the effects of friction on rolling objects and how it impacts acceleration.
  • Explore advanced kinematics concepts, such as projectile motion and energy conservation.
  • Investigate the relationship between slope angle and acceleration in inclined planes.
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Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of motion and acceleration in rolling objects.

j1249
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a steel ball, starting from rest rolls down one slope and up another. it takes 2.5s to reach the bottom of the first slope, at which point its speed is 5.0 m/s. if the magnitutde of the acceleration on the second slope is exactly one-half that on the first slope, how long will it take for the ball to come to a stop on the second slope?
 
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The key is to get a value of the acceleration on the first slope. You should be able to get that by using the values given in

v=at

where v is the final velocity, a is the acceleration and t is the time.
 
alright great thanks a lot! :)
 

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