Rolling Steel Ball Acceleration Questions

AI Thread Summary
To determine how long it takes for the steel ball to stop on the second slope, first calculate the acceleration on the first slope using the formula v = at, where the final velocity (v) is 5.0 m/s and the time (t) is 2.5 s. This gives an acceleration of 2.0 m/s² on the first slope. The acceleration on the second slope is half of this, resulting in 1.0 m/s². Using the same formula, the time to stop on the second slope can be calculated as 5.0 seconds. Thus, it takes the ball 5.0 seconds to come to a stop on the second slope.
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a steel ball, starting from rest rolls down one slope and up another. it takes 2.5s to reach the bottom of the first slope, at which point its speed is 5.0 m/s. if the magnitutde of the acceleration on the second slope is exactly one-half that on the first slope, how long will it take for the ball to come to a stop on the second slope?
 
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The key is to get a value of the acceleration on the first slope. You should be able to get that by using the values given in

v=at

where v is the final velocity, a is the acceleration and t is the time.
 
alright great thanks alot! :)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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