Romeo's Pebbles - A Zero Horizontal Acceleration Problem

AI Thread Summary
Romeo is trying to calculate the speed of pebbles when they hit Juliet's window, given a vertical distance of 7.90 m and a horizontal distance of 8.50 m. The initial calculations were flawed due to the use of incorrect equations for a two-dimensional motion problem. The correct approach involves separating the vertical and horizontal motions and applying the appropriate kinematic equations. After correcting the formulas, the final speed of the pebbles upon impact was determined to be 6.69 m/s. Understanding the trajectory and using the right equations is crucial for solving such physics problems effectively.
EcKoh
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Homework Statement



Romeo is chucking pebbles as gently as he can up to Juliet's window. That is, he wants the pebbles to hit the wendow with the least possible speed. He is standing at the edge of a rose garden at Dv = 7.90 m below her window and at Dh = 8.50 m from the base of the wall. How fast are the pebbles going when they hit her window?

Homework Equations



Vf = Vi + adv (to find initial velocity)
Vf = Vi + at (to find hang time)
Dh = Vht (to find constant horizontal velocity)


The Attempt at a Solution



Okay so I'm assuming I did everything right, so I'm not sure where I went wrong but here are the steps I took in my attempt:

3.1: List knowns and unknowns:

Knowns:
Vf = 0 m/s
a = -9.8 m/s2
Dv = 7.90 m
DH = 8.50 m

Unknowns:
Vi = ?

3.2: Find the initial velocity:

Vf = Vi + adv
(0) = Vi + (-9.8)(7.90)
Vi = 77.42

3.3: Find hang time:

Vf = Vi + at
(0) = (77.42) + (-9.8)t
-77.42 = -9.8t
t = 7.9s <-- (maybe I went wrong here? I noticed that's the same as Dv

3.4: Find constant velocity:

Dh = Vht
(8.50) = Vh(7.9)
Vh = 1.08

So 1.08 m/s turns out to be the wrong answer, and I keep going back and reworking it but I'm not sure what I'm doing wrong. Its due online tonight in just a few hours, but either way it's driving me crazy so I just want to know what I'm doing wrong and how to fix it.

Thanks!
 
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Hi EcKoh, welcome to PF.
In the relevant equations, the first equation is wrong. Check that.
 
Yes, vf != v0 + ad, rather, v^2 = v0^2 +2ad
 
What you are doing wrong is treat this two dimensional problem as if it were one-dimensional. You need to write the vertical and horizontal equations of motion. Then you need to consider at what part of the trajectory the speed is a minimum. Also, your equation
vf=vi+adv is incorrect.
 
Thanks guys, I corrected the formula and was able to get a correct answer of 6.69 m/s
 
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