Rotation at an angle - Tether ball (Finding length)

AI Thread Summary
A tether ball is attached to a 3m tall pole and is swung at a speed of 9.5 m/s, creating an angle of 32° with the vertical. The initial calculations for the radius of rotation yielded an impractically large value, raising concerns about the problem's setup. The discussion revealed that the radius of 14.7m implies a string length of approximately 27.7m, which contradicts the pole height. Participants acknowledged the discrepancy and suggested that the issue lies within the problem itself rather than the calculations. The conversation concluded with a sense of camaraderie among the contributors as they navigated the complexities of the problem.
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Homework Statement


A tether ball is a ball at the end of a rope tied to a pole 3m tall. A player whips the ball around with a speed of 9.5 m/s and the string rises to an angle of 32°. Find the length of the string.

length of pole = 3m
v = 9.5
angle θ = 32°

Homework Equations


Fnet = ma



The Attempt at a Solution


I drew the FBD on the diagram itself

http://sadpanda.us/images/857602-GFGQJ1G.jpg

I know I did something wrong because the radius I got is way too big.
 
Last edited by a moderator:
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testme said:

Homework Statement


A tether ball is a ball at the end of a rope tied to a pole 3m tall. A player whips the ball around with a speed of 9.5 m/s and the string rises to an angle of 32°. Find the length of the string.

length of pole = 3m
v = 9.5
angle θ = 32°

Homework Equations


Fnet = ma



The Attempt at a Solution


I drew the FBD on the diagram itself

http://sadpanda.us/images/857602-GFGQJ1G.jpg

I know I did something wrong because the radius I got is way too big.

Actually, your value matches the given information of angle and velocity. It doesn't accord very well with the supposed 3m height of the pole though! And it gets worse when you consider that 14.7m is just the radius of rotation; the string length h will be about twice that!

Looks like a problem with the problem itself, not your work :smile:
 
Last edited by a moderator:
Oh, damn.. I left the next question cause it was the same idea.

So to calculate h ot wpi;d ne

Fx = 14. 7m

14.7 h
----- = ----
sin32 sin 90

h = 27.7 m?
 
testme said:
Oh, damn.. I left the next question cause it was the same idea.

So to calculate h ot wpi;d ne

Fx = 14. 7m

14.7 h
----- = ----
sin32 sin 90

h = 27.7 m?

That looks about right :wink:
 
Thanks a lot, that damn question threw me off.

Anyways, I'm off to bed. G'night everyone who reads this :)
 
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