- #1
Nanuven
- 11
- 0
Force F = (9.0 N) i hat + (-4.0 N) k hat acts on a pebble with position vector r = (3.00 m) j hat + (-1.0 m) k hat, relative to the origin.(a) What is the resulting torque acting on the pebble about the origin?
( N·m) i hat + ( N·m) j hat + ( N·m) k hat
(b) What is the resulting torque acting on the pebble about a point with coordinates (0.0 m, 0.0 m, 5.0 m)?
( N·m) i hat + ( N·m) j hat + ( N·m) k hat
So all I could come up with was cross product was that torque = r cross F
Therefore T = fRsin[tex]\theta[/tex]
I looked up cross product on Wikipedia (not best site I know but w/e) and it came up with:
i x j = k
j x k = i
k x i = j
I tried those but it doesn't seem to be giving me the right answer. Any help please??
( N·m) i hat + ( N·m) j hat + ( N·m) k hat
(b) What is the resulting torque acting on the pebble about a point with coordinates (0.0 m, 0.0 m, 5.0 m)?
( N·m) i hat + ( N·m) j hat + ( N·m) k hat
So all I could come up with was cross product was that torque = r cross F
Therefore T = fRsin[tex]\theta[/tex]
I looked up cross product on Wikipedia (not best site I know but w/e) and it came up with:
i x j = k
j x k = i
k x i = j
I tried those but it doesn't seem to be giving me the right answer. Any help please??