Rotational Motion maximum speed

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Homework Help Overview

The problem involves a car moving on an un-banked curve, focusing on determining the maximum speed without skidding, given the mass of the car, the radius of the curve, and the coefficients of friction.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the formula involving kinetic friction but questions the discrepancy with the answer key. Some participants suggest considering static friction instead, emphasizing its relevance when the vehicle is not sliding.

Discussion Status

The discussion is exploring the appropriate use of friction coefficients in the context of the problem. Participants are actively questioning assumptions about the type of friction applicable to the scenario, with some guidance provided regarding the use of static friction.

Contextual Notes

There is a noted confusion regarding the application of kinetic versus static friction in the context of the car's motion on the curve. The original poster's approach and the answer key's response are under scrutiny.

physgrl
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Homework Statement



3. A 1500 kg car is moving on an un-banked curve with a radius of 98 m. The coefficients of static and kinetic friction are 0.73 and 0.50 respectively. The maximum speed the car can move without skidding is:

*a. 27 m/s

b. 22.4m/s

c. 21 m/s

d. 30 m/s

e. none of the above


Homework Equations



Fn*μ=mv2/r


The Attempt at a Solution



I used that formula with the coefficient of kinetic friction (because the object is in motion when it has velocity) and I got 21.9...the answer key says its 27.
 
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Have you tried using static friction? Until the vehicle begins drifting, you only have static friction. At every instant in time, the rubber that is in contact with the road surface is not moving relative to the road surface. It's called the instantaneous center.
 
physgrl said:
I used that formula with the coefficient of kinetic friction (because the object is in motion when it has velocity) and I got 21.9...the answer key says its 27.
If the car is not sliding sideways, you would use the coefficient of static friction. The static friction force is perpendicular to the direction of motion at all times.

AM
 
Ohhh got it i was thinking about friction in the other direction. Thanks
 

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