# Rotational Motion of a marble

## Homework Statement

A solid uniform marble and a block of ice, each with the same mass, start from rest at the same height H above the bottom of a hill and move down it. The marble rolls without slipping, but the ice slides without friction.

Find the speed of each of these objects when it reaches the bottom of the hill.
Vice:?
Vmarble:?

1/m v^2 = mgh

## The Attempt at a Solution

Ice:
1/2 mv^2=mgh

v= squareroot 2gh

Marble:
mgh=1/2 mv^2 + 1/2 I ω^2

=1/2 mv^2 +1/2(2/5 mr^2) (v/r)^2

The answers i entered in were marked incorrect by masteringphysics.

Related Introductory Physics Homework Help News on Phys.org
I like Serena
Homework Helper
Hi valerie! x0x

Your v for the block of ice is correct.
And your equation for the marble is correct too.

The only thing missing is that you didn't give v of the marble.
Did you solve your equation for v?

well i got stuck.... and i dont know why its marking me wrong. for the marble i got v: squareroot 2/4 mgh

anythoughts?

I like Serena
Homework Helper
well i got stuck.... and i dont know why its marking me wrong. for the marble i got v: squareroot 2/4 mgh

anythoughts?
I'm afraid that in that case you did not solve your own equation correctly.

For starters, there should not be an "m" in there.
There isn't an "m" for the block of ice either!

But your fraction of 2/4 is wrong too.

How did you arrive at your solution for v?
Can you show some (major) steps?

oh never mind .......... this stupid mastering physics wanted a capital H instead of h.

aughhhhhh!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! the marble was squareroot 10 gh/7

thanks for your help!!!!!! i caught that at the last min!

I like Serena
Homework Helper