(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The fraction of [tex]6.0 MeV[/tex] protons scattered by thin gold foil, of density [tex]\rho=19.3 g/cm^{3}[/tex], from the incident beam into a region where scattering angles exceed [tex]60 degrees[/tex] is equal to [tex] 2.0 x 10^{-5} [/tex]. Calculate the thickness of the gold foil using the result of the previous problem.

2. Relevant equations

The result I got for the previous problem was a formula for the number of particles scattered thru and angle of [tex]\theta[/tex] or greater and is:

[tex]N(\theta)= (\frac{1}{4\pi\epsilon_{0}})^{2} \pi I \rho t (\frac{zZe^{2}}{Mv^{2}})^{2} cot^{2}(\frac{\theta}{2}) [/tex]

3. The attempt at a solution

So I took [tex]\frac{N(\theta)}{I}[/tex] which is equivalent to removing the I from the above equation and attempted to solve for t, which is the thickness...

[tex]t=\frac{2x10^{-5}}{(\frac{1}{4\pi\epsilon_{0}})^{2} \pi (19.3 g/cm^{3}) (\frac{79(1.602x10^{-19}coul)^{2}}{2(6 MeV)})^{2} cot^{2}(\frac{\pi}{6})}[/tex]

problem is that I keep getting an answer in m/kg, so I must be missing some term, though I can't figure out what it is...

any help is very much appreciated.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Rutherford scattering calculation

**Physics Forums | Science Articles, Homework Help, Discussion**