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Homework Statement
show what integral of 1/(1-xy)dxdy = pi^{2}/6
dx 0 to 1
dy 0 to 1
remember[tex]\int[/tex]1/(1-xy)dx = ln(1-xy) = ln(1-y) - ln1
[tex]\int[/tex]ln(1-y) - ln1 dy = (1-y)ln(1-y) - (1- y) - yln1
= -ln1 - (ln1 - 1) = = -2ln1 + 1 huh