DivGradCurl
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I'm just not so sure on how to approach this problem. Well, here it goes:
\sum _{n=1} ^{\infty} \left[ \tan ^{-1} (n+1) - \tan ^{-1} (n) \right] = \frac{\pi}{2}
I know that
\tan ^{-1} x = \sum _{n=0} ^{\infty} \left( -1 \right) ^n \frac{x^{2n+1}}{2n+1}
but I don't know if it can be useful to get to the answer above. I just need some tips. Any help is highly appreciated.
\sum _{n=1} ^{\infty} \left[ \tan ^{-1} (n+1) - \tan ^{-1} (n) \right] = \frac{\pi}{2}
I know that
\tan ^{-1} x = \sum _{n=0} ^{\infty} \left( -1 \right) ^n \frac{x^{2n+1}}{2n+1}
but I don't know if it can be useful to get to the answer above. I just need some tips. Any help is highly appreciated.
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