Shearing Force Direction in Fluid Mechanics

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The discussion centers on the direction of shearing forces in two fluid mechanics diagrams. It is clarified that shear forces require opposing directions to effectively "tear" an object. The first diagram is deemed correct as it illustrates opposing forces acting on a control volume, while the second diagram is also correct, showing the same shear force exerted by a stationary wall on moving fluid. The fluid dynamics at play involve varying velocities that influence the direction of the forces. Overall, both diagrams accurately represent the shearing forces involved.
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Homework Statement


why the shearing force acting on the object in the first diagram is in different direction , while in the second photo , it's in same direction ?

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The Attempt at a Solution


in my opinion , it should be in different direction , because the shearing force must be applied in 2 different direction , so that the object will be 'teared' . Which is correct?
 

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Of the four shear force vectors shown in your figures, when specific ones do you think are drawn correctly (if any), which specific ones do you think are drawn incorrectly (if any), and why.
 
Chestermiller said:
Of the four shear force vectors shown in your figures, when specific ones do you think are drawn correctly (if any), which specific ones do you think are drawn incorrectly (if any), and why.
i think the first one is correct , because the shearing force must be applied in 2 different direction , so that the object will be 'teared' . i think the second 1 is incorrect
 
goldfish9776 said:
i think the first one is correct , because the shearing force must be applied in 2 different direction , so that the object will be 'teared' . i think the second 1 is incorrect
Yes, shear force requires opposing forces, but in the second diagram there are four forces, and one of them goes the other way. Both diagrams are correct.
 
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I agree with haruspex. The directions of all 4 shear forces are drawn correctly in the diagrams.

In the first diagram, you are doing a shell (control volume) force balance on the fluid within the cylindrical shell between r and r + Δr. The fluid at radii greater than r + Δr is traveling more slowly than the fluid within the shell, so it is dragging the fluid in the control volume backwards (to the left). The fluid at radii less than r is traveling more rapidly than the fluid within the shell, so it is dragging the fluid in the control volume forwards (to the right).

In the second diagram, the arrow at the bottom and the arrow at the top actually represent the exact same shear force exerted by the wall on fluid filling the tube (or channel). Since the wall is stationary and the fluid is moving to the right, the wall exerts a drag force on the fluid to the left.

Chet
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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