- #1

- 971

- 40

## Homework Statement

## Homework Equations

## The Attempt at a Solution

Considering the upper hemispherical liquid part ,the forces acting on it are , force due to the shell and that due to the bottom liquid .

Doing a force balance , force due to upper hemispherical shell = ##\pi R^3ρg - \frac{2}{3}\pi R^3ρg = \frac{1}{3}\pi R^3ρg## (downwards)

Force due to the liquid on upper hemisphere would be ## \frac{1}{3}\pi R^3ρg## (upwards) gives option A) for Q 13 .

For Q 14 , I think rotating the shell doesn't rotate the liquid which means the pressure at point P should remain unaffected i.e option A )

Is that correct ?

Thanks