Shell Method Problem: Solve x=y^(2), x=4 About the X-Axis

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Homework Statement


x=y^(2), x=4, about the x axis.

Homework Equations



2pi* integral from a to b of radius*height of function*thickness

The Attempt at a Solution


I have 2pi* integral from -2 to 2 of y*(4-y^(2)) dy but that does not make any sense. Answer comes out to be 0. The real answer is 8pi. I know how to do this with the disk method just not the shell method. Thank for the help!
 
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hi hvidales! :smile:
hvidales said:
… integral from -2 to 2 …

noooo :wink:
 
I see and thanks. However, how come for this problem: y=x^(2), y=2-x^(2), about x=1 the limits are from -1 to 1 ?
 
you mean x goes from -1 to 1?

that's because the body in that case goes from x = -1 to x = 3 (the reflection about x = 1)

in your first example the body went from y = -2 to y = 2

in each case, you're taking half (because each single cylindrical shell is in both halves) :wink:
 
Thank you!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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