A 29.0 kg block at rest on a horizontal frictionless air track is connected to the wall via a spring. The equilibrium position of the mass is defined to be at x=0. Somebody pushes the mass to the position x=.350 m, then lets go. The mass undergoes simple harmonic motion with a period of 3.50 s. What is the position of the mass 2.975 s after the mass is released?(adsbygoogle = window.adsbygoogle || []).push({});

I got this part fine, with an answer of .206 m

Consider the same mass and spring discussed in the previous problem. What is the magnitude of the maximum acceleration the mass undergoes during its motion?

I found the angular velocity by using

[tex]\omega = 2\pi/ T [/tex] and got it to be 1.795. I then plugged it into the equation, [tex] a= -\omega^2 x_{m}cos(\omega t +\theta) [/tex]

with x= .206 m, and t=2.975 s. I got a= .389 m/S^2, which isn't right.

can someone tell me what I'm doing wrong?

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# Homework Help: SHM acceleration problem

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