Show the velocity graph of a 4.7 kg object as it moves along the x-axis

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To determine the force acting on a 4.7 kg object using the equation F = m•a, one must multiply the object's mass by its acceleration at a specific time, as indicated by the y-axis of a velocity-time graph. The calculations provided show that multiplying 4.7 kg by different velocities (6 m/s, 12 m/s, and 3 m/s) results in momentum values of 28.2 kg m/s, 56.4 kg m/s, and 14.1 kg m/s, respectively. The discussion emphasizes that the y-axis represents velocity, and thus the product with mass gives momentum. Additionally, the equation F = dp/dt is relevant for understanding the relationship between force and momentum change over time. This highlights the connection between force, mass, and velocity in motion analysis.
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Homework Statement
Figure 1 shows the velocity graph of a 4.7 kg object as it moves along the x-axis.
A) What is the x- component of the net force acting on this object at t = 1s?
B) At 3s?
C) At 7s?
Relevant Equations
F=M•a
If force= m•a would the answer just be the y-axis • 4.7 at the specific time such as
A) 4.7 • 6 = 28.2?
B) 4.7 • 12= 56.4
C) 4.7 • 3 = 14.1
 
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Post Figure 1. (If you have a velocity-time graph, how would you find the acceleration at any point?)
 
I solved it! Sorry for the late response, if you’re still wondering.
image.jpg
 
Cb8 said:
If force= m•a would the answer just be the y-axis • 4.7 at the specific time such as
A) 4.7 • 6 = 28.2?
B) 4.7 • 12= 56.4
C) 4.7 • 3 = 14.1
Since the y-axis shows velocity (in m/s) multiplying the y-axis by the mass of 4.7 (in kg) yields momentum (in kg m/s).

A relevant equation would be: ##F=\frac{dp}{dt}##
 
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