Show the velocity graph of a 4.7 kg object as it moves along the x-axis

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Homework Help Overview

The discussion revolves around the velocity graph of a 4.7 kg object moving along the x-axis, focusing on the relationship between force, mass, and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of the equation force = mass × acceleration, questioning how to derive acceleration from a velocity-time graph. There are attempts to calculate momentum using the velocity values from the graph.

Discussion Status

Some participants have provided calculations based on the mass and velocity values, while others have posed questions about finding acceleration from the velocity graph. There is an indication of ongoing exploration of the concepts involved.

Contextual Notes

Participants are discussing the implications of multiplying velocity by mass to derive momentum, and there is mention of relevant equations without reaching a consensus on the overall approach.

Cb8
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Homework Statement
Figure 1 shows the velocity graph of a 4.7 kg object as it moves along the x-axis.
A) What is the x- component of the net force acting on this object at t = 1s?
B) At 3s?
C) At 7s?
Relevant Equations
F=M•a
If force= m•a would the answer just be the y-axis • 4.7 at the specific time such as
A) 4.7 • 6 = 28.2?
B) 4.7 • 12= 56.4
C) 4.7 • 3 = 14.1
 
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Post Figure 1. (If you have a velocity-time graph, how would you find the acceleration at any point?)
 
I solved it! Sorry for the late response, if you’re still wondering.
image.jpg
 
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Cb8 said:
If force= m•a would the answer just be the y-axis • 4.7 at the specific time such as
A) 4.7 • 6 = 28.2?
B) 4.7 • 12= 56.4
C) 4.7 • 3 = 14.1
Since the y-axis shows velocity (in m/s) multiplying the y-axis by the mass of 4.7 (in kg) yields momentum (in kg m/s).

A relevant equation would be: ##F=\frac{dp}{dt}##
 

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