Signal not neriodic if multiplied by decaying exponential?

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The signal x(t) = e^{jt} is periodic, while x(t) = e^{-t}e^{jt} is not periodic due to the influence of the decaying exponential, which causes the signal to converge toward zero. The key reason for the non-periodicity is the inability to find a real T such that x(t) = x(t+nT). Additionally, the signal x(t) = e^{-t}e^{jt} is not considered time-limited since it never actually reaches zero. The discussion highlights the importance of understanding the conditions for periodicity in signals. Overall, the analysis clarifies the behavior of these signals in relation to periodicity and time limitation.
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The signal x(t) = e^{jt} is periodic.

The signal x(t) = e^{-t}e^{jt} is not periodic.

The decaying exponential makes the complex exponential decay and converge toward zero, but why is it not periodic?

Also, this signal is not considered time limited since it never actually reaches zero. Right?
 
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SpaceDomain said:
The signal x(t) = e^{jt} is periodic.

The signal x(t) = e^{-t}e^{jt} is not periodic.

The decaying exponential makes the complex exponential decay and converge toward zero, but why is it not periodic?

Because you can't find a real T such that x(t)=x(t+nT).
 
Neat. I was thinking about this qualitatively and forgot about the required condition you mentioned.

Thanks.

Is what I said about it not being time limited correct?
 
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