Engineering Signal & System CTFT: Find x(t) from X(ω)

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SUMMARY

The discussion focuses on finding the continuous-time signal x(t) from its continuous-time Fourier transform (CTFT) X(ω). Participants explore the use of Fourier Transform tables to assist in solving the problem, particularly regarding limits involving exponential functions. A specific expression, exp(n(jt-1/2))-1, is analyzed as n approaches infinity, leading to a conclusion that it converges to -1. The conversation highlights the importance of understanding the behavior of exponential functions in Fourier analysis.

PREREQUISITES
  • Continuous-Time Fourier Transform (CTFT)
  • Fourier Transform tables
  • Complex exponential functions
  • Limit evaluation techniques in calculus
NEXT STEPS
  • Study the properties of the Continuous-Time Fourier Transform (CTFT)
  • Review Fourier Transform tables for common pairs
  • Learn about the convergence of complex exponential functions
  • Practice limit evaluation techniques in the context of Fourier analysis
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Students and professionals in electrical engineering, signal processing, and applied mathematics who are working with Fourier transforms and analyzing continuous-time signals.

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Homework Statement
Find the CT signal associated with CTFT:
Relevant Equations
.
Given the CTFT X(ω): 1638042527872.png
1638042702750.png

and here are my solution to find CT signal x(t) associated with the given CTFT , but i got stuck at the limit part
 
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BvU said:
FInd any hints in a table of FTs ?

##\ ##
Oh, my professor never mention this, i will check this and see
Thank you
 
##\exp(n(jt-1/2))-1\to -1## as ##n\to \infty## since ##\exp(jtn)=\cos(tn)+j\sin(tn)## and ##\exp(-n/2)\to 0## as ##n\to \infty##.
 
MathematicalPhysicist said:
##\exp(n(jt-1/2))-1\to -1## as ##n\to \infty## since ##\exp(jtn)=\cos(tn)+j\sin(tn)## and ##\exp(-n/2)\to 0## as ##n\to \infty##.
Yes i have tried this before, but it didn't match the solution that my professor gave, that's why i ask in here to check
1638093425950.png
 

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