Simple Circuit for high power LED

AI Thread Summary
A simple circuit for a 3V high power LED can be designed using a resistor in series with the LED, calculated based on the supply voltage. For a 9V battery, a resistor of (9-3)/0.8 Ohm is needed, while for a 4.5V battery, it would be (4.5-3)/0.8 Ohm. It's crucial to use a resistor with a suitable power rating, ideally at least 10 watts, to manage the heat generated. Using multiple LEDs in series or a buck switching regulator can improve efficiency and reduce heat output significantly. Voltage regulator ICs like LM317 or L7805 are included to maintain constant brightness as battery voltage decreases.
selseg
Messages
32
Reaction score
0
What simple circuit that I can design for a 3V high power LED with max current 0.8 amps , I think the component names would help me , I would like to power it on 4.5 to 9 V batteries .Preferably lower voltages. Thanks
 
Engineering news on Phys.org
Connect the 9v battery to the led in series with a (9-3)/.8 Ohm resistor.

On a 4.5v battery use a (4.5-3)/.8 ohm resistor.
 
Antiphon said:
Connect the 9v battery to the led in series with a (9-3)/.8 Ohm resistor.

On a 4.5v battery use a (4.5-3)/.8 ohm resistor.

Just make sure the resistor has suitable power rating - in the above scenario, the resistor is dropping 6 volts at 0.8A, which is 4.8 watts. I'd use at least a 10 watt resistor in that case, and that is going to be a LOT of heat... it would need mounted on a pretty beefy heatsink. The LED will need mounted on a big heatsink too.

If the OP can do it, it would be better to have more LED's in series rather than burning all that power as heat, or if you want to get more advanced, a buck switching regulator will get you into the 90%+ efficiency range and make the battery last 3 times longer and massively reduce the heat output.
 
These are voltage regulator ICs that ensure the LED is constant brightness even as the battery voltage drops lower.
 
Last edited by a moderator:
You may want some size-D or lantern batteries for something that draws this much current. (3) size D alkalines have a nominal voltage of 4.5. That might get you there without wasting too much of your power as heat.
 
selseg said:
Thank you very much , I checked from the link below earlier on . Why do they include the LM317 in that circuit ? in another circuit i found online , they used l7805. Why do they include these ics and capacitor ?
http://www.instructables.com/id/Super-simple-high-power-LED-driver/?ALLSTEPS
They're using voltage regulator chips in a "constant current" configuration.
 
Back
Top