• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Simple Harmonic Motion and pendulum clock

  • Thread starter Ogir28
  • Start date
1. The problem statement, all variables and given/known data

What will be better to take to the moon, a spring clock or a pendulum clock. Why?

2. Relevant equations

F= -k*(Delta)x

k = g m/Dx

T = 2*π*[square-root of:(m/k)]


3. The attempt at a solution

I know that there is less gravitational force while on the moon... Just dont see what the difference would be between block clocks. they both depend on gravity in the same manner...
 
I'm not sure... but doesn't the equation read F=-kx, but k is NOT dependent on g? couldn't the spring be sideways?
 
well Usually weve been doing mass spring problems vertically, else, he would have told us... but what would be the factor that would affect a change in k while on the moon???
 
the only things that the equation involves are: mass, gravity, k constant
 
A pendulum would be better. For a pendulum, period is about 2pi*sqrt(l/g) This is dependent on g, which is different in the moon. It is dependent on g, because g is the restoring force which brings the mass at the end of the string back to equilibrium position. However, for a spring block oscillator, the mass of the object (ideally) doesn't contribute to the restoring force, which is just -k(Dx), and the period is independent of g.

Hope this helped.
 

dx

Homework Helper
Gold Member
2,004
18
The spring clock would be better because it will run at the same rate on the moon as it does on earth.
 
thank you guys very much.
 

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top