Simple Harmonic Motion Tuning Fork Question

[ninjagowoowoo]

Q:
A tuning fork vibrates at a frequency of 264 Hz and the tip of each prong moves 1.66 mm to either side of center. Calculate the maximum speed of the tip of a prong.

So far I've found that Vmax = omega*A, but I don't know how to find A. Am I going in the wrong direction? Or is there a way to find A that I don't know about yet..?

 

[Doc Al]

... the tip of each prong moves 1.66 mm to either side of center.

That's the amplitude.

 

[ninjagowoowoo]

Oh haha, I knew it must've been something stupid, thanks.

 

[ninjagowoowoo]

Ok so I figured that Vmax would be omega*A, but it isn't correct. I know that
v=-omega*A*sin(omega*t) (yeah I need to learn how to write equations better)

so I assumed that in the problem, it's basically an initial value, so t=0. So that would leave v=omega*A.

From this I got Vmax = (2pi/T)(A)
and T=1/f

so Vmax = (2pi/(1/f))(A)

I guess this is incorrect. Oh and I didnt forget to convert mm to m. Any pointers?
Thanks

 

[ninjagowoowoo]

woops nevermind... I must have entered it in my calculator wrong haha sorry. Thanks for the help Al.