Simple pendulum and harmonic motion

AI Thread Summary
The period of a simple pendulum is calculated using the formula T=2π*(sqrt(L/g)), where L is the length of the pendulum and g is the acceleration due to gravity. In this scenario, the pendulum is in an elevator accelerating upward at 5.90 m/s², which alters the effective gravitational force acting on it. To find the correct period, the effective gravitational acceleration must be adjusted to account for the elevator's upward acceleration, resulting in g' = g + a. The confusion arises from the need to incorporate this adjusted gravitational force into the period calculation, which is crucial for accurately determining the pendulum's motion in a non-stationary frame of reference. Understanding this adjustment is key to solving the problem correctly.
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Homework Statement



A simple pendulum is 5.20 m long. What is the period of simple harmonic motion for this pendulum if it is hanging in an elevator that is accelerating upward at 5.90 m/s2?


Homework Equations



T=2pi*(sqrt(L/g))

The Attempt at a Solution



all I did was plug in the value of the length of the pendulum into the equation like so:
T=2pi*(sqrt(5.2/9.8))=4.58s
but this answer is not right? I'm so confused as to what I am supposed to do and why I am given acceleration if I don't even need it.
 
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If you know how to derive this equation you are using, I would go through it and look at where the gravitational acceleration, g, comes in. If the pendulum is feeling a vertical acceleration from the elevator now, in addition to the gravitational acceleration, how would that affect your derivation/equation?
 
You're not in a stationary frame of reference. You're in an accelerating frame of reference. Think about it. When you are in an elevator that is accelerating upward (e.g. when it first begins to move) do you feel lighter, heavier, or nothing at all?

It's almost as if a mysterious force has cropped up ;)
 
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