mstehman
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I have to find the Force Horizontally and Vertically.
My equation for Fh is cos(60)(AB) - cos(45)(BC) = 0
My equation for Fv is sin 60 (AB) + sin 45 (BC) – 1000 = 0
I don't recall how to move things around, what to divide etc. Basically i need a step by step explained so i can learn and recall hopefully how.
These were rules for what to do also:
You can use either equation to write an expression for either AB or BC, then substitute the value you find in the OTHER equation. You must substitute into the other equation in order to solve for an answer
Please Help!
My equation for Fh is cos(60)(AB) - cos(45)(BC) = 0
My equation for Fv is sin 60 (AB) + sin 45 (BC) – 1000 = 0
I don't recall how to move things around, what to divide etc. Basically i need a step by step explained so i can learn and recall hopefully how.
These were rules for what to do also:
You can use either equation to write an expression for either AB or BC, then substitute the value you find in the OTHER equation. You must substitute into the other equation in order to solve for an answer
Please Help!