Simple truss question I can't seem to get right

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The discussion revolves around a truss problem where the user is struggling to calculate the reaction forces and member forces correctly. They initially calculate the reaction forces at the pin and roller but realize they may have overlooked the vertical component of the load at point C, which creates an additional moment about point A. This oversight affects the calculations, leading to an incorrect result for the force in member BD, which should be 12.89 kN in compression. The user acknowledges the mistake after receiving feedback. Clarifying the moments due to both horizontal and vertical components is crucial for accurate truss analysis.
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Homework Statement


p6v4LnW.png


bRYWUNP.jpg


ignore all the other writing!

The Attempt at a Solution


I can't tell where I'm making a mistake. Probably a massive oversight somewhere but I don't know where!

First find the reaction forces at the pin and roller by treating everything as a rigid body. (I am now aware this isn't necessary since I can start at joint D since one of the equations has 1 unknown, but this method is still bugging me)

sum F_x = 0
R_Dx + R_Ax - 5000sin(15) = 0 (equation 1)

sum F_y = 0
-R_Ay - 5000cos(15) = 0
so R_Ay = -4829 N

sum Moments about point A = 0
(2*R_Dx) - (5*5000sin(15)) = 0
so R_Dx = 3235 N

so plugging R_Dx into equation 1 gives
R_Ax = -1941 Nstarting at joint D

sum F_x = 0

R_Dx + BD = 0
so BD = -R_Dx = -3235 N

but the answer says it is 12.89 kN compression!
I can't continue because everything else will be wrong.

What am I screwing up on?
 
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nothingsus said:

Homework Statement


p6v4LnW.png


bRYWUNP.jpg


ignore all the other writing!

The Attempt at a Solution


I can't tell where I'm making a mistake. Probably a massive oversight somewhere but I don't know where!

First find the reaction forces at the pin and roller by treating everything as a rigid body. (I am now aware this isn't necessary since I can start at joint D since one of the equations has 1 unknown, but this method is still bugging me)

sum F_x = 0
R_Dx + R_Ax - 5000sin(15) = 0 (equation 1)

sum F_y = 0
-R_Ay - 5000cos(15) = 0
so R_Ay = -4829 N

sum Moments about point A = 0
(2*R_Dx) - (5*5000sin(15)) = 0
so R_Dx = 3235 N

so plugging R_Dx into equation 1 gives
R_Ax = -1941 Nstarting at joint D

sum F_x = 0

R_Dx + BD = 0
so BD = -R_Dx = -3235 N

but the answer says it is 12.89 kN compression!
I can't continue because everything else will be wrong.

What am I screwing up on?
It appears you have accounted for the moments about A due to the horizontal component of the load at C.

However, additional moment at A will be created due to the vertical component of the load at C, since this component is offset horizontally from the line A-D.
 
SteamKing said:
It appears you have accounted for the moments about A due to the horizontal component of the load at C.

However, additional moment at A will be created due to the vertical component of the load at C, since this component is offset horizontally from the line A-D.

Dang, can't believe I missed that.

Thanks for the reply!
 
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